0=3.49(x^2)+x-4.64

Solution for 0=3.49(x^2)+x-4.64 equation:

0=3.49(x^2)+x-4.64

We move all terms to the left:

0-(3.49(x^2)+x-4.64)=0

We add all the numbers together, and all the variables

-(3.49x^2+x-4.64)=0

We get rid of parentheses

-3.49x^2-x+4.64=0

We add all the numbers together, and all the variables

-3.49x^2-1x+4.64=0

a = -3.49; b = -1; c = +4.64;
Δ = b2-4ac
Δ = -12-4·(-3.49)·4.64
Δ = 65.7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{65.7744}}{2*-3.49}=\frac{1-\sqrt{65.7744}}{-6.98}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{65.7744}}{2*-3.49}=\frac{1+\sqrt{65.7744}}{-6.98}
$